3 \$\begingroup\$ The energy stored in a capacitor is \$\frac{1}{2}C\times{}V^2\$. Yet a potential difference is itself a measure of the energy stored per unit of charge. (with units Joule per Coulomb). Shouldn't the voltage across a capacitor directly relate, then, to the amount of energy it stores, instead of the square root of it? voltagecapacitorunits Share Cite Follow edited yesterday TimWescott 47.1k11 gold badge4545 silver badges109109 bronze badges asked yesterday stickynotememostickynotememo 35922 silver badges1313 bronze badges \$\endgroup\$ 2 3 \$\begingroup\$ Because the surface area of a right-angled triangle grows quadratically with the length of its leg ;-). \$\endgroup\$ – Peter - Reinstate Monica Commented 16 hours ago \$\begingroup\$ More voltage means more charge, and also more energy per charge. \$\endgroup\$ – Peter Cordes Commented 12 hours ago Add a comment  |